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@chitacan
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Last active August 29, 2015 14:07
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Mario Klingemann has made some beautiful Voronoi diagrams. This is my attempt to recreate them using D3. To achieve the curved cells, each side of the Voronoi polygon is subdivided into three equal-length segments and then joined using the "basis-closed" line interpolator. There are some discontinuities in the animation when the sides of a polygon approach zero which could likely be avoided by adding a minimum-length threshold to the subdivision.

If you’d like to see other instances of this pattern, Mario describes the algorithm on Flickr.

<!DOCTYPE html>
<meta charset="utf-8">
<style>
body {
background: #000;
}
path {
fill: #fff;
stroke: #000;
stroke-width: 1.5px;
}
</style>
<body>
<script src="http://d3js.org/d3.v3.min.js"></script>
<script>
var width = 960,
height = 500;
var points = [];
var bounds = d3.geom.polygon([
[-width / 2, -height / 2],
[-width / 2, +height / 2],
[+width / 2, +height / 2],
[+width / 2, -height / 2]
]);
circle(0, 0, 120, 96, -.001);
circle(0, 0, 30, 10, .03);
circle(0, 0, 60, 3, -.05);
circle(0, 0, 15, 4, -.02);
circle(0, 0, 0, 1, -.02);
circle(240, -120, 80, 4, -.02);
circle(240, -120, 0, 1, -.02);
circle(280, +120, 40, 8, .02);
circle(280, +120, 20, 8, -.02);
circle(280, +120, 0, 1, .02);
var line = d3.svg.line()
.interpolate("basis-closed");
var svg = d3.select("body").append("svg")
.attr("width", width)
.attr("height", height)
.append("g")
.attr("transform", "translate(" + (width / 2) + "," + (height / 2) + ")");
var path = svg.selectAll("path")
.data(points)
.enter().append("path");
d3.timer(function() {
var voronoi = d3.geom.voronoi(points).map(function(cell) { return bounds.clip(cell); });
path.attr("d", function(point, i) { return line(resample(voronoi[i])); });
});
function circle(cx, cy, r, n, δθ) {
d3.range(1e-6, 2 * Math.PI, 2 * Math.PI / n).map(function(θ) {
var point = [cx + Math.cos(θ) * r, cy + Math.sin(θ) * r];
d3.timer(function() {
θ += δθ;
point[0] = cx + Math.cos(θ) * r;
point[1] = cy + Math.sin(θ) * r;
});
points.push(point);
return point;
});
}
function resample(points) {
var i = -1,
n = points.length,
p0 = points[n - 1], x0 = p0[0], y0 = p0[1], p1, x1, y1,
points2 = [];
while (++i < n) {
p1 = points[i], x1 = p1[0], y1 = p1[1];
points2.push(
[(x0 * 2 + x1) / 3, (y0 * 2 + y1) / 3],
[(x0 + x1 * 2) / 3, (y0 + y1 * 2) / 3],
p1
);
p0 = p1, x0 = x1, y0 = y1;
}
return points2;
}
</script>
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