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Last active August 15, 2021 11:32
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Animating a line with an arrow in d3
<!doctype html>
<html lang="en">
<head>
<meta charset="utf-8" />
<title>Animating a line with an arrow in d3</title>
<script src="http://d3js.org/d3.v3.min.js" charset="utf-8"></script>
<style>
.line {
stroke: blue;
stroke-width: 1.5px;
fill: white;
}
circle {
fill: red;
}
#marker {
stroke: black;
fill: black;
}
</style>
</head>
<body>
<div id="chart">
<script language="javascript">
"use strict"
var svg = d3.select("body").append("svg").append("g").attr("transform", "translate(100,50)")
svg.append("svg:defs")
.append("svg:marker")
.attr("id", "arrow")
.attr("refX", 2)
.attr("refY", 6)
.attr("markerWidth", 13)
.attr("markerHeight", 13)
.attr("orient", "auto")
.append("svg:path")
.attr("d", "M2,2 L2,11 L10,6 L2,2");
var line = d3.svg.line()
.x( function(point) { return point.lx; })
.y( function(point) { return point.ly; });
function lineData(d){
// i'm assuming here that supplied datum
// is a link between 'source' and 'target'
var points = [
{lx: d.source.x, ly: d.source.y},
{lx: d.target.x, ly: d.target.y}
];
return line(points);
}
var path = svg.append("path")
.data([{source: {x : 0, y : 0}, target: {x : 80, y : 80}}])
.attr("class", "line")
//.style("marker-end", "url(#arrow)")
.attr("d", lineData);
//var arrow = svg.append("svg:path")
//.attr("d", "M2,2 L2,11 L10,6 L2,2");
console.log(d3.svg.symbol())
var arrow = svg.append("svg:path")
.attr("d", d3.svg.symbol().type("triangle-down")(10,1));
arrow.transition()
.duration(2000)
.ease("linear")
.attrTween("transform", translateAlong(path.node()))
//.each("end", transition);
// Returns an attrTween for translating along the specified path element.
function translateAlong(path) {
var l = path.getTotalLength();
var ps = path.getPointAtLength(0);
var pe = path.getPointAtLength(l);
var angl = Math.atan2(pe.y - ps.y, pe.x - ps.x) * (180 / Math.PI) - 90;
var rot_tran = "rotate(" + angl + ")";
return function(d, i, a) {
console.log(d);
return function(t) {
var p = path.getPointAtLength(t * l);
return "translate(" + p.x + "," + p.y + ") " + rot_tran;
};
};
}
var totalLength = path.node().getTotalLength();
path
.attr("stroke-dasharray", totalLength + " " + totalLength)
.attr("stroke-dashoffset", totalLength)
.transition()
.duration(2000)
.ease("linear")
.attr("stroke-dashoffset", 0);
</script>
</body>
</html>
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