This is in answer to this google groups question. The aim was to create a colour scale that wasn't biased by underlying distribution of the data. To achieve this an ordinal scale was used in conjunction with a custom colour interpolation.
Created
June 5, 2014 19:15
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Colour interpolation
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| <!DOCTYPE html> | |
| <html> | |
| <head> | |
| <meta charset="utf-8"> | |
| <meta http-equiv="X-UA-Compatible" content="IE=edge,chrome=1"> | |
| <title>Interpolated Colour Scales</title> | |
| <script type="text/javascript" src="http://d3js.org/d3.v3.min.js"></script> | |
| </head> | |
| <body> | |
| </body> | |
| <script type="text/javascript"> | |
| var data = [10, 20, 100, 101, 102, 103, 104,105, 500, 700, 1000], | |
| dataRange = []; | |
| for (var i = 0; i < data.length; i++) { | |
| dataRange.push((i+1)/data.length) | |
| }; | |
| var colourScale = d3.scale.ordinal() | |
| .domain(data) | |
| .range(dataRange); | |
| d3.select("body").selectAll("div") | |
| .data(data).enter() | |
| .append("div") | |
| .style("height", "25px") | |
| .style("width", function(d) { | |
| return d + "px"; | |
| }) | |
| .style("background", function (d,i) { | |
| return interp(colourScale(d)); | |
| }) | |
| .style("margin", "2px"); | |
| function interp(x) { | |
| var ans = d3.interpolateLab("#ff0000", "#0000ff")(x); | |
| return ans | |
| } | |
| </script> | |
| </html> |
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