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borestad/backbone.$super.js

Created August 7, 2012 13:50
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super call within Backbone.js
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backbone.$super.js
var $super = function(funcName){
funcName = funcName || 'initialize';
// _.bindAll messes upp constructor
// TODO: Add more tests with multiple inheritance
var _super = this.constructor.__super__ || this.__proto__.constructor.__super__;
return _super[funcName].apply(this, _.rest(arguments));
},
_$super = function(funcName){
funcName = funcName || 'initialize';
// _.bindAll messes upp constructor
// TODO: Add more tests with multiple inheritance
var _super = this.constructor.__super__ || this.__proto__.constructor.__super__;
return _super[funcName];
};
// Create a superclass method
Backbone.Model.prototype.$super =
Backbone.Collection.prototype.$super =
Backbone.NestedModel.prototype.$super =
Backbone.View.prototype.$super = $super;
Backbone.Model.prototype._$super =
Backbone.Collection.prototype._$super =
Backbone.NestedModel.prototype._$super =
Backbone.View.prototype._$super = _$super;
@danroberts
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Hey... I'm not sure if the way I did it is very clean or not... but if you check out my fork, I think I've made it work so that you can do multiple levels of inheritance...

The problem is that you need a reference to both the actual backbone model, and the prototype chain as you continue to move up the inheritance tree. If you keep it at this... than this.constructor.super will always point to one level above the SubChild, causing an infinite loop.

If you keep a reference to the actual backbone model, which I'm calling $that, you can bind the initialize context to $that, while keeping the prototype context to the proper this as you move up the change.

Let me know if this makes any sense or seems correct to you.

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