Created
April 28, 2016 15:57
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Solution to https://technology.jana.com/2016/04/26/challenge-your-python-knowledge puzzle #4
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| # solution to https://technology.jana.com/2016/04/26/challenge-your-python-knowledge/ | |
| # puzzle 4, in the original version (with the typo) | |
| # replacing __repr__ without typing double underscores | |
| # selected deque, because it has a method (pop) that | |
| # 1) has no arguments | |
| # 2) modifies the object | |
| # 3) can return a string | |
| from ctypes import * | |
| from collections import deque | |
| import sys | |
| ptr_size = sizeof(c_void_p) | |
| a = c_void_p.from_address(id(deque)+11*ptr_size) | |
| b = c_void_p.from_address(id(deque)+29*ptr_size).value | |
| if sys.version_info.major == 2: | |
| c = c_void_p.from_address(b + 29*ptr_size) | |
| else: | |
| c = c_void_p.from_address(b + 41*ptr_size) | |
| a.value = c.value | |
| mystery1 = {'a': deque(['a', 'a'])} | |
| mystery2 = {'a': deque(['a', 'b'])} | |
| assert type(mystery1) is dict | |
| assert type(mystery2) is dict | |
| assert str(mystery1) != str(mystery2) | |
| assert str(mystery1) == str(mystery2) | |
| print("All checks passed") |
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