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@denjn5
Last active September 27, 2017 10:49
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Simple Tree (d3 v4; CSV; 63 Lines)
license: gpl-3.0
height: 200
border: no

This is the simplest horizontal tree diagram I could create. Let me know if you think I can make it tighter.

Build notes:

  • It pulls data from a csv file. It uses d3.stratify() to reform links into a hierarchy.
  • To differentiate between local variables and framework objects, I prefix variables with lowercase 'v'.

From https://bl.ocks.org/denjn5/4bdda16ab6338772a7882ec2f5f2a9c7

We can make this file beautiful and searchable if this error is corrected: It looks like row 2 should actually have 3 columns, instead of 2. in line 1.
id,parentId,size
cars,
owned,cars
traded,cars
learned,cars
pilot,owned,40
325ci,owned,40
accord,owned,20
chevette,traded,10
odyssey,learned,20
maxima,learned,10
<!DOCTYPE html>
<meta charset='utf-8'>
<head>
<title>Simple Tree (d3 v4; CSV; 63 Lines)</title>
<script src="https://d3js.org/d3.v4.min.js"></script>
</head>
<style>
circle {
stroke: #05668D;
fill: white;
opacity: 0.6;
stroke-width: 2px;
}
path {
fill: none;
stroke: #05668D;
opacity: 0.6;
stroke-width: 2px;
}
</style>
<svg>
<g></g>
</svg>
<script>
var vWidth = 300;
var vHeight = 200;
// Prepare our physical space
var g = d3.select('svg').attr('width', vWidth).attr('height', vHeight)
.select('g').attr('transform', 'translate(20,20)');
// Get the data from our CSV file
d3.csv('data.csv', function(error, vCsvData) {
if (error) throw error;
vData = d3.stratify()(vCsvData);
drawViz(vData);
});
function drawViz(vData) {
// Declare d3 layout
var vLayout = d3.tree().size([vHeight * 0.9, vWidth * 0.8]);
// Layout + Data
var vRoot = d3.hierarchy(vData);
var vNodes = vRoot.descendants();
var vLinks = vLayout(vRoot).links();
// Draw on screen
g.selectAll('path').data(vLinks).enter().append('path')
.attr('d', d3.linkHorizontal()
.x(function(d) { return d.y; })
.y(function(d) { return d.x; }));
g.selectAll('circle').data(vNodes).enter().append('circle')
.style('r', 10)
.attr('transform', function (d) { return 'translate(' + d.y + ',' + d.x + ')'; });
}
</script>
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