Created
November 9, 2020 23:38
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/** | |
* Returns the URL of a hyperlinked cell, if it's entered with hyperlink command. | |
* Supports ranges | |
* @param {A1} reference Cell reference | |
* @customfunction | |
*/ | |
function linkURL(reference) { | |
var sheet = SpreadsheetApp.getActiveSheet(); | |
var formula = SpreadsheetApp.getActiveRange().getFormula(); | |
var args = formula.match(/=\w+\((.*)\)/i); | |
try { | |
var range = sheet.getRange(args[1]); | |
} | |
catch(e) { | |
throw new Error(args[1] + ' is not a valid range'); | |
} | |
var formulas = range.getRichTextValues(); | |
var output = []; | |
for (var i = 0; i < formulas.length; i++) { | |
var formula = formulas[i] | |
var urls = []; | |
var urlsStr = ""; | |
for (var j = 0; j < formula.length; j++) { | |
var run = formula[j].getRuns(); | |
for (var k = 0; k < run.length; k++) { | |
var url = run[k].getLinkUrl(); | |
if (url != null) { | |
urlsStr += run[k].getText() + " " + run[k].getLinkUrl() + "\n"; | |
} | |
} | |
} | |
output.push(urlsStr); | |
} | |
return output | |
} |
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I cannot use the result of this function as a parameter of IMPORTRANGE. It works in two steps:
For example in the cell E25 I have a link.
With =linkURL(E25), I get the link, for example in E26 and then with
=IMPORTRANGE(E26; ADDRESS(72;1))
I get the correct result.
But with
=IMPORTRANGE(linkURL(E25); ADDRESS(72;1))
I get
#ERROR !
Any idea why ?
Thanks
Marc